20 ml of 0.2 M \(\mathrm{Al_2SO_4}\) is mixed with 20 ml of 0.6 M \(\mathrm{BaCl_2}\) Concentration of \(\mathrm{Al_3}\) ion in the solution will be

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentMEDIUMJEE Chemistry
20 ml of 0.2 M \(\mathrm{Al_2SO_4}\) is mixed with 20 ml of 0.6 M \(\mathrm{BaCl_2}\) Concentration of \(\mathrm{Al_3}\) ion in the solution will be **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** MEDIUM | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

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## ✅ Correct Answer: **A** ### 📖 Detailed Explanation: This question uses mole concept & stoichiometry. Relate mass, moles and number of particles using the mole concept and basic stoichiometry; doing the algebra gives the value listed in option A. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentMEDIUMJEE Chemistry