Question No. 1 to 3 (3 questions) (i) P + C(carbon) + Cl2 Q + CO (ii) Q + H2O R + HCl (iii) BN + H2O R + NH3 (iv) Q + LiAlH4 S + LiCl + AlCl3 (v) S + H2O R + H2 (vi) S + NaH T (P, Q, R, S and T do not

Question

Question No. 1 to 3 (3 questions)
(i) P + C(carbon) + Cl2 $\rightarrow$ Q + CO $\uparrow$
(ii) Q + H2O $\rightarrow$ R + HCl
(iii) BN + H2O $\rightarrow$ R + NH3 $\uparrow$
(iv) Q + LiAlH4 $\rightarrow$ S + LiCl + AlCl3
(v) S + H2O $\rightarrow$ R + H2 $\uparrow$
(vi) S + NaH $\rightarrow$ T
(P, Q, R, S and T do not represent their chemical symbols)

Prashant Kotian · Accepted Answer

Correct answer: C. Reactions are:
(i) B2O3(P) + 3C + 3Cl2 2BCl3(Q) + 3CO
(ii) BCl3(Q) + 3H2O H3BO3(R) + 3HCl
Hence Q is BCl3 which has zero dipole moment, is planar trigonal, and is an electron deficient compound.

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