Practical Organic Chemistry and PurificationhardNUMERICAL

While estimating the nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolvPractical Organic Chemistry and Purification Chemistry Question

Question

While estimating the nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.25 g of the compound neutralized 2.5 mL of 2 M H SO . The percentage of nitrogen present in organic compound is . . . . . . . . 2 4

Answer: 56

💡 Solution & Explanation

**Step 1: Determine moles of H₂SO₄** Moles of H₂SO₄ = Molarity × Volume (L) Moles of H₂SO₄ = 2 M × 0.0025 L = 0.005 mol **Step 2: Determine moles of NH₃ using stoichiometry** The neutralization reaction is: 2NH₃ + H₂SO₄ → (NH₄)₂SO₄ From the equation: 1 mol H₂SO₄ neutralizes 2 mol NH₃ Moles of NH₃ = 2 × 0.005 = 0.01 mol **Step 3: Determine moles of nitrogen** Each NH₃ molecule contains 1 nitrogen atom Moles of N = 0.01 mol **Step 4: Calculate mass of nitrogen** Atomic mass of N = 14 g/mol Mass of N = 0.01 mol × 14 g/mol = 0.14 g **Step 5: Calculate percentage of nitrogen** Percentage of N = (Mass of N / Mass of compound) × 100 Percentage of N = (0.14 g / 0.25 g) × 100 = 56% Therefore, the answer is 56.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry