If the conductivity of mercury at 0°C is 1.07 × 10 S m and the resistance of a cell containing mercu — Electrochemistry Chemistry Question

💡 Solution & Explanation

**Step 1: Identify the relationship between conductivity, resistance, and cell constant.** The formula relating these quantities is: $$\kappa = G \times a$$ Where: - κ = conductivity (S m⁻¹) - G = conductance (S) = 1/R - a = cell constant (m⁻¹) **Step 2: Rearrange to solve for cell constant.** $$a = \frac{\kappa}{G} = \kappa \times R$$ **Step 3: Substitute the given values.** - κ = 1.07 × 10⁶ S m⁻¹ - R = 0.243 Ω $$a = 1.07 \times 10^6 \times 0.243$$ **Step 4: Calculate the cell constant.** $$a = 0.26001 \times 10^6 \text{ m}^{-1}$$ $$a = 2.6001 \times 10^5 \text{ m}^{-1}$$ **Step 5: Express in the form x × 10⁴ m⁻¹.** $$a = 26.001 \times 10^4 \text{ m}^{-1}$$ **Step 6: Round to the nearest integer.** x = 26.00 Therefore, the answer is **26.00**.