SO3^2- + S* -boil- SS*O3^2-, SS*O3^2- + 2H+ - H2SO3 + S*. The above reaction sequence proves:

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SO3^2- + S* -boil-> SS*O3^2-, SS*O3^2- + 2H+ -> H2SO3 + S*. The above reaction sequence proves:

Prashant Kotian · Accepted Answer

Correct answer: A. The starred sulphur precipitates back during decomposition, showing the two S atoms maintain their identity and are not equivalent.

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