The correct code for stability, of oxidation states for given cations is :<br>(i) Pb2+ > Pb4+, Tl+ < — p Block Elements Chemistry Question
Question
The correct code for stability, of oxidation states for given cations is :<br>(i) Pb2+ > Pb4+, Tl+ < Tl3+<br>(ii) Bi3+ < Sb3+, Sn2+ < Sn4+<br>(iii) Pb2+ > Pb4+, Bi3+ > Bi5+<br>(iv) Tl3+ < In3+, Sn2+ > Sn4+<br>(v) Sn2+ < Pb2+, Sn4+ > Pb4+<br>(vi) Sn2+ < Pb2+, Sn4+ < Pb4+
Answer: C
💡 Solution & Explanation
Due to inert effect the stability of lower oxidation state gradually increases while stability of higher oxidation state gradually decreases down the group in elements of group 13th to 15th. So correct orders are :<br>(iii) Pb2+ > Pb4+, Bi3+ > Bi5+<br>(iv) Sn2+ < Pb2+, Sn4+ > Pb4+
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