Qualitative and Quantitative AnalysismediumMCQ SINGLE

A white powder "A" on heating gave a non-combustible gas and a white residue. The residue on heatingQualitative and Quantitative Analysis Chemistry Question

Question

A white powder "A" on heating gave a non-combustible gas and a white residue. The residue on heating turns yellow. The residue dissolves in dil. HCl and the solution gives a white ppt. with K4[Fe(CN)6]. "A" would be:

Answer: B

💡 Solution & Explanation

ZnCO3(s) -Δ-> ZnO(s) + CO2(g). ZnO is yellow when hot, white when cold. ZnO + 2HCl -> ZnCl2 + H2O. 3Zn2+ + 2K4[Fe(CN)6] -> K2Zn3[Fe(CN)6]2 + 6K+ (white ppt.).

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry