K2[Ni(CN)4] --K in liq. NH3--> 'X'<br>Regarding this reaction correct statement is/are: — Coordination Compounds Chemistry Question

💡 Solution & Explanation

K reduces Ni(II) to Ni(0), forming K4[Ni(CN)4]. Ni(0) is d^10, resulting in sp^3 hybridization (tetrahedral geometry) for 'X'. The reactant [Ni(CN)4]^2- has Ni(II) which is d^8 and dsp^2 hybridized (square planar).