A white solid forms Rinmann's green in the charcoal cavity test in an oxidising flame. On treatment — Qualitative and Quantitative Analysis Chemistry Question
Question
A white solid forms Rinmann's green in the charcoal cavity test in an oxidising flame. On treatment with dilute H2SO4, this solid produces a gas that turns an acidified dichromate paper green and lead acetate paper black. The white solid is:
Answer: C
💡 Solution & Explanation
Rinmann's green indicates Zn. Gas turning dichromate green (by reduction to Cr3+) and lead acetate black (PbS) is H2S, confirming a sulphide. Hence, ZnS.
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