Select the correct statement(s) regarding BF2NH2 molecule : — Chemical Bonding Chemistry Question

💡 Solution & Explanation

According to Bent's rule there is more p-character in B—F bond than in B—N bond; hence FBF is less than 120°. As size of —NH2 group is larger than F-atom hence repulsion between —NH2 group and F-atoms is higher than between two F-atoms. As lone pair of N-atom in NH2 group participate in back bonding hence H—N—H is greater than 109°28', as hybridization of N is changing from sp^3 towards close to sp^2.