Chem Mantra
⚗️ Chem-MantraJEE Advanced Chemistry →
p Block ElementsmediumNUMERICAL

The difference between total number of lone pairs and total number of -bonds in [B3O3(OH)6]^3- molec — p Block Elements Chemistry Question

Question

The difference between total number of lone pairs and total number of $\sigma$-bonds in [B3O3(OH)6]^3- molecular ion is :

Answer: 0 / TOTAL NUMBER OF $\SIGMA$-BONDS = 18. TOTAL NUMBER OF LONE PAIRS = 18
💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

Explore Courses →Free on YouTube

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry