X(s) (Black) -dil HCl-> Y↑ -Na2[Fe(CN)5(NO)] / NaOH-> Purple solution Gas Y. Gas Y has been allowed — Qualitative and Quantitative Analysis Chemistry Question
Question
X(s) (Black) -dil HCl-> Y↑ -Na2[Fe(CN)5(NO)] / NaOH-> Purple solution Gas Y. Gas Y has been allowed to react with following species in neutral/acidic medium : (a) FeCl3 (b) CuSO4 (c) BaCl2 (d) SO2 (e) Cr2O7^2- (f) CH3COONa (g) Hg2+. Then calculate value of (P + Q - R). P : Number of species which undergoes redox reaction with gas Y. Q : Number of species with which gas Y undergoes precipitation. R : Number of species with which gas Y produce no observable change.
Answer: 3
💡 Solution & Explanation
Y is H2S (from FeS + dil HCl). P = 3 (FeCl3, SO2, Cr2O7^2- undergo redox), Q = 2 (CuSO4, Hg2+ undergo precipitation), R = 2 (BaCl2, CH3COONa show no observable change). Value of (P + Q - R) = 3 + 2 - 2 = 3.
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