Na2O2 P + Q <br> Na2O2 P + R + S <br> Calculate sum of bond order between same bonded atoms in Q and — s Block Elements Chemistry Question
Question
Na2O2 $\xrightarrow{\text{Water, } 0^\circ\text{C}}$ P + Q <br> Na2O2 $\xrightarrow{\text{Water, } 25^\circ\text{C}}$ P + R$\uparrow$ + S <br> Calculate sum of bond order between same bonded atoms in Q and R compounds.
Answer: 3 <BR><BR>**SOLUTION:**<BR>NA2O2 $\XRIGHTARROW{\TEXT{H}_2\TEXT{O, } 0^\CIRC\TEXT{C}}$ NAOH (P) + H2O2 (Q)<BR>NA2O2 $\XRIGHTARROW{\TEXT{WATER, } 25^\CIRC\TEXT{C}}$ NAOH (P) + O2$\UPARROW$ (R) + H2O (S)<BR>BOND ORDER OF [O-O] IN H2O2 = 1.0<BR>BOND ORDER OF [O-O] IN O2 = 2.0<BR>SUM OF BOND ORDER BETWEEN SAME BONDED ATOMS IN Q AND R COMPOUNDS = 1 + 2.0 = 3.0
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