Consider the following changes : M(s) - M(g) ...(1) ; M(s) - M2+(g) + 2e- ...(2) ; M(g) - M+(g) + e- ...(3) ; M+(g) - M2+(g) + e- ...(4) ; M(g) - M2+(g) + 2e- ...(5). The second ionization energy

Question

Consider the following changes : M(s) -> M(g) ...(1) ; M(s) -> M2+(g) + 2e- ...(2) ; M(g) -> M+(g) + e- ...(3) ; M+(g) -> M2+(g) + e- ...(4) ; M(g) -> M2+(g) + 2e- ...(5). The second ionization energy of M could be calculated from the energy values associated with :

Prashant Kotian · Accepted Answer

Correct answer: D. Second ionization energy is amount of energy required to take out an electron from the monopositive cation. Hence, M(g) -> M2+ + 2e- ...(5) and M(g) -> M+ + e- ...(3)

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