Consider the following reactions of complex compounds A, B and C
(i) CoCl2Br \cdot 5NH3 + excess Ag^+ (aq.) \rightarrow 1AgCl(s) (Compound A)
(ii) CoCl2Br \cdot 5NH3 + excess Ag^+ (aq.) \rightar

Question

Consider the following reactions of complex compounds A, B and C
(i) CoCl2Br \cdot 5NH3 + excess Ag^+ (aq.) \rightarrow 1AgCl(s) (Compound A)
(ii) CoCl2Br \cdot 5NH3 + excess Ag^+ (aq.) \rightarrow 2AgCl(s) (Compound B)
(iii) CoCl2Br \cdot 4NH3 + excess Ag^+ (aq.) \rightarrow 1AgCl(s) (Compound C)
Then according to the given information the correct statement(s) is/are :

Prashant Kotian · Accepted Answer

Correct answer: A,B,D. Compound A is [CoCl(NH3)5]BrCl, B is [CoBr(NH3)5]Cl2. Both furnish 3 ions in solution, so molar conductivities are nearly the same. Since Cl^- is a stronger ligand than Br^-, CFSE order is \Delta_o(A) > \Delta_o(B) > \Delta_o(C).

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