In the estimation of bromine, 0.5 g of an organic compound gave 0.40 g of silver bromide. The percen — Practical Organic Chemistry and Purification Chemistry Question

💡 Solution & Explanation

**Step 1: Identify the molar mass of AgBr** Molar mass of AgBr = 108 + 80 = 188 g/mol **Step 2: Calculate moles of AgBr formed** Moles of AgBr = 0.40 g ÷ 188 g/mol = 0.00213 mol **Step 3: Determine moles of Br in the compound** From the formula AgBr, 1 mole of AgBr contains 1 mole of Br. Therefore, moles of Br = 0.00213 mol **Step 4: Calculate mass of Br** Mass of Br = 0.00213 mol × 80 g/mol = 0.170 g **Step 5: Calculate percentage of Br in the organic compound** Using the formula: $$\text{Percentage of Br} = \frac{\text{Mass of Br}}{\text{Mass of compound}} × 100$$ $$\text{Percentage of Br} = \frac{0.170}{0.5} × 100 = 34\%$$ Therefore, the answer is 34.00.