CrO4^2- (yellow) changes to Cr2O7^2- (orange) in pH = x and vice-versa in pH = y. Hence, x and y are : | d and f Block Elements — Chem-Mantra | Chem-Mantra

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Question

CrO4^2- (yellow) changes to Cr2O7^2- (orange) in pH = x and vice-versa in pH = y. Hence, x and y are :

Answer: A

💡 Solution & Explanation

2CrO4^2- + 2H^+ $\rightarrow$ Cr2O7^2- + H2O<br>Cr2O7^2- + 2OH^- $\rightarrow$ 2CrO4^2- + H2O

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