For the following molecules : PCl5, BrF3, ICl2^-, XeF5^-, NO3^-, XeO2F2, PCl4^+, CH3^+ Calculate the — Chemical Bonding Chemistry Question
Question
For the following molecules : PCl5, BrF3, ICl2^-, XeF5^-, NO3^-, XeO2F2, PCl4^+, CH3^+ Calculate the value of (a + b) / c. a = Number of species having sp^3d-hybridisation. b = Number of species which are planar. c = Number of species which are non-planar.
Answer: ANSWER: 3
💡 Solution & Explanation
PCl5 -> sp^3d, non-planar; BrF3 -> sp^3d, bent, T-shape, planar; ICl2^- -> sp^3d, linear, planar; XeF5^- -> sp^3d^3, pentagonal planar; NO3^- -> sp^2, planar; XeO2F2 -> sp^3d, see-saw, non-planar; PCl4^+ -> sp^3, tetrahedral, non-planar; CH3^+ -> sp^2, Trigonal planar. a = 4, b = 5, c = 3 so, (a+b)/c = 3.
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