Inorganic benzene reacts with HCl to form a compound B3N3H9Cl3. The protonation occurs at : | Chemical Bonding — Chem-Mantra | Chem-Mantra

⚗️ Chem-Mantra JEE Advanced Chemistry →

Chemical BondingmediumMCQ SINGLE

Question

Inorganic benzene reacts with HCl to form a compound B3N3H9Cl3. The protonation occurs at :

Answer: B

💡 Solution & Explanation

[SEE DIAGRAM] The protonation (H+) occurs at the N-atom and Cl- attacks the B-atom.

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

Explore Courses →Free on YouTube

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry