There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 2.5 respectively and rest two species S

Question

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, 
Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 
2.5 respectively and rest two species S and T are heteronuclear diatomic species
and have bond order 3 and 2 respectively. All homonuclear diatomic species are 
paramagnetic and all heteronuclear diatomic species are diamagnetic in nature. 
P, R, S and T are monovalent positive ion and Q is monovalent negative ion :

Prashant Kotian · Accepted Answer

Correct answer: C. P : \sigma 1s^2 < \sigma^* 1s^2 < \sigma 2s^2 < \sigma^* 2s^2 < \pi 2p_x^2 < \pi 2p_y^2 < \sigma 2p_z^1. By removing one e^-, P becomes diamagnetic from paramagnetic. Bond order of P(i.e., N2^+) < Bond order of N2. R retains paramagnetic behaviour by adding one e^-, and T becomes paramagnetic from diamagnetic by adding one e^-.

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