3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. The volume of oxygen adsorbed per gram of t — Surface Chemistry Chemistry Question

💡 Solution & Explanation

**Step 1: Calculate moles of oxygen adsorbed** Mass of O₂ = 3.12 g Molar mass of O₂ = 32 g/mol Moles of O₂ = 3.12 g ÷ 32 g/mol = 0.0975 mol **Step 2: Use the ideal gas law to find volume** PV = nRT Where: - P = 1 atm - n = 0.0975 mol - R = 0.082 L·atm/(mol·K) - T = 300 K V = nRT/P = (0.0975 mol × 0.082 L·atm/(mol·K) × 300 K) / 1 atm V = 2.40 L **Step 3: Calculate volume per gram of adsorbent** Mass of platinum (adsorbent) = 1.2 g Volume per gram of Pt = 2.40 L ÷ 1.2 g = 2.00 L/g Therefore, the answer is 2.00.