There is mixture of Cu(II) chloride and Fe(II) sulphate. The best way to separate the metal ions from this mixture in qualitative analysis is: | Qualitative and Quantitative Analysis — Chem-Mantra | Chem-Mantra

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Qualitative and Quantitative AnalysiseasyMCQ SINGLE

Question

There is mixture of Cu(II) chloride and Fe(II) sulphate. The best way to separate the metal ions from this mixture in qualitative analysis is:

Answer: A

💡 Solution & Explanation

Cu2+ is second group radical, gets precipitated first due to having lower solubility product [CuS-Ksp = 1 x 10^-44]

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