Qualitative and Quantitative AnalysiseasyMCQ SINGLE

Brown ppt. (A) dissolve in HNO3 gives (B) which gives white ppt. (C) with NH4OH. (C) on reaction witQualitative and Quantitative Analysis Chemistry Question

Question

Brown ppt. (A) dissolve in HNO3 gives (B) which gives white ppt. (C) with NH4OH. (C) on reaction with HCl gives solution (D) which gives white turbidity on addition of water. What is (D)?

Answer: A

💡 Solution & Explanation

Bi2S3 + 8HNO3 (dil.) -hot-> 2Bi(NO3)3 + 3S + 2NO + 4H2O. Bi(NO3)3 + 3NH4OH -> Bi(OH)3(C) + 3NH4NO3. Bi(OH)3 + 3HCl -> BiCl3(D) + 3H2O. BiCl3 + H2O <=> BiOCl(white turbidity) + 2HCl

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry