A (Light pink colour complex) HMnO4 A (Light pink colour complex).<br>Calculate CFSE value in light — Coordination Compounds Chemistry Question
Question
A (Light pink colour complex) $\xrightarrow{Pb3O4/dil.HNO3}{\Delta}$ HMnO4 $\xrightarrow{H2S/H^+}$ A (Light pink colour complex).<br>Calculate CFSE value in light pink colour complex.
Answer: **ANSWER: 0**<BR>SOLUTION: THE LIGHT PINK COLOUR COMPLEX IS [MN(H2O)6]^2+. MN^2+ IS 3D^5 AND HAS $\DELTA_O$ < P, GIVING A T2G^3 EG^2 CONFIGURATION. CFSE = 3 $\TIMES$ (-2/5 $\DELTA_O$) + 2 $\TIMES$ (3/5 $\DELTA_O$) = 0.
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