SbF5 reacts with XeF4 to form an adduct. The shapes of cation and anion in the adduct are respectively: | p Block Elements — Chem-Mantra | Chem-Mantra

⚗️ Chem-Mantra JEE Advanced Chemistry →

p Block ElementsmediumMCQ SINGLE

Question

SbF5 reacts with XeF4 to form an adduct. The shapes of cation and anion in the adduct are respectively:

Answer: B

💡 Solution & Explanation

XeF4 + SbF5 $\rightarrow$ [XeF3]+[SbF6]-. [XeF3]+ is sp3d hybridized, bent T shape. [SbF6]- is sp3d2 hybridized, octahedral.

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

Explore Courses →Free on YouTube

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry