Consider the following representation based on long form of periodic table. [SEE DIAGRAM] Value of all four quantum number for last electron of element 'X' in their ground state is n = 4, l = 1, m = 1

Question

Consider the following representation based on long form of periodic table.
[SEE DIAGRAM]
Value of all four quantum number for last electron of element 'X' in their 
ground state is n = 4, l = 1, m = 1 and s = -1/2 and spin multiplicity of 
element 'X' in their ground state is 4.

Prashant Kotian · Accepted Answer

Correct answer: D. X is "As" => [Ar] 3d10 4s2 4p3. 2s+1 = 4, s = 3/2. So unpaired electron in element X is 3.

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