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If a pure sample of an oxide of sulfur contains 40. percent sulfur and 60. percent oxygen by mass, tStoichiometry Chemistry Question

Question

If a pure sample of an oxide of sulfur contains 40. percent sulfur and 60. percent oxygen by mass, then the empirical formula of the oxide is

A.

SO3

✓ Correct
B.

SO4

C.

S2O6

D.

S2O8

💡 Solution & Explanation

STEPS:

1. Understand the definition of an empirical formula: An empirical formula represents the simplest, lowest whole-number ratio of the elements present in a chemical compound.
2. Assume a convenient sample size: To easily convert the given mass percentages into tangible masses, assume a 100.0 g sample of the sulfur oxide. Under this assumption:
* The mass of sulfur (S\text{S}) is exactly 40.0 g40.0\text{ g}.
* The mass of oxygen (O\text{O}) is exactly 60.0 g60.0\text{ g}.
3. Convert the mass of each element to moles: Use the average atomic molar masses from the periodic table:
* For Sulfur (Molar Mass32.06 g/mol\text{Molar Mass} \approx 32.06\text{ g/mol}):
Moles of S=40.0 g32.06 g/mol1.25 mol S\text{Moles of S} = \frac{40.0\text{ g}}{32.06\text{ g/mol}} \approx \mathbf{1.25\text{ mol S}}
* For Oxygen (Molar Mass16.00 g/mol\text{Molar Mass} \approx 16.00\text{ g/mol}):
Moles of O=60.0 g16.00 g/mol=3.75 mol O\text{Moles of O} = \frac{60.0\text{ g}}{16.00\text{ g/mol}} = \mathbf{3.75\text{ mol O}}
4. Determine the simplest molar ratio: Divide the number of moles of each element by the smallest number of moles calculated (1.25 mol1.25\text{ mol}):
* Ratio for S: 1.251.25=1\frac{1.25}{1.25} = \mathbf{1}
* Ratio for O: 3.751.25=3\frac{3.75}{1.25} = \mathbf{3}
5. Write the empirical formula: Because the molar ratio of S\text{S} to O\text{O} is exactly 1:31:3, the empirical formula of the sulfur oxide is SO3\text{SO}_3, which identifies Option A as the correct answer.

*

WHY_OTHERS_WRONG:

  • Option B is incorrect (SO4\text{SO}_4): If the compound were sulfur tetroxide (SO4\text{SO}_4), the molar ratio of sulfur to oxygen would be 1:41:4. This corresponds to a mass composition of approximately 33.4%33.4\% sulfur and 66.6%66.6\% oxygen, which is inconsistent with the given data.
  • Option C is incorrect (S2O6\text{S}_2\text{O}_6): Although the ratio of atoms in S2O6\text{S}_2\text{O}_6 is chemically equivalent to the correct mass percentage, an empirical formula must show the lowest whole-number ratio of atoms. S2O6\text{S}_2\text{O}_6 is a molecular formula because it can be mathematically simplified down to SO3\text{SO}_3.
  • Option D is incorrect (S2O8\text{S}_2\text{O}_8): This represents a molecular formula that simplifies to the empirical formula SO4\text{SO}_4 (representing 25.0%25.0\% sulfur and 75.0%75.0\% oxygen by mass). It is neither the lowest whole-number ratio nor does it match the specified mass percentage composition of the sample.
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