If a pure sample of an oxide of sulfur contains 40. percent sulfur and 60. percent oxygen by mass, t — Stoichiometry Chemistry Question
Question
If a pure sample of an oxide of sulfur contains 40. percent sulfur and 60. percent oxygen by mass, then the empirical formula of the oxide is
SO3
SO4
S2O6
S2O8
💡 Solution & Explanation
STEPS:
1. Understand the definition of an empirical formula: An empirical formula represents the simplest, lowest whole-number ratio of the elements present in a chemical compound.
2. Assume a convenient sample size: To easily convert the given mass percentages into tangible masses, assume a 100.0 g sample of the sulfur oxide. Under this assumption:
* The mass of sulfur () is exactly .
* The mass of oxygen () is exactly .
3. Convert the mass of each element to moles: Use the average atomic molar masses from the periodic table:
* For Sulfur ():
* For Oxygen ():
4. Determine the simplest molar ratio: Divide the number of moles of each element by the smallest number of moles calculated ():
* Ratio for S:
* Ratio for O:
5. Write the empirical formula: Because the molar ratio of to is exactly , the empirical formula of the sulfur oxide is , which identifies Option A as the correct answer.
*
WHY_OTHERS_WRONG:
- Option B is incorrect (): If the compound were sulfur tetroxide (), the molar ratio of sulfur to oxygen would be . This corresponds to a mass composition of approximately sulfur and oxygen, which is inconsistent with the given data.
- Option C is incorrect (): Although the ratio of atoms in is chemically equivalent to the correct mass percentage, an empirical formula must show the lowest whole-number ratio of atoms. is a molecular formula because it can be mathematically simplified down to .
- Option D is incorrect (): This represents a molecular formula that simplifies to the empirical formula (representing sulfur and oxygen by mass). It is neither the lowest whole-number ratio nor does it match the specified mass percentage composition of the sample.