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Acids and BasesMCQ

30. When a small amount of 12 M HNO3(aq) is added to a buffer solution made by mixing CH3NH2(aq) andAcids and Bases Chemistry Question

Question

  1. When a small amount of 12 M HNO3(aq) is added to a buffer solution made by mixing CH3NH2(aq) and CH3NH3Cl(aq), the pH of the buffer solution changes from 10.64 to 10.62. Which of the following equations represents the reaction that accounts for the fact that the pH does not change significantly when the HNO3(aq) is added?
A.

CH3NH2(aq) + H+(aq) → CH3NH3+(aq)

✓ Correct
B.

CH3NH3+(aq) + H+(aq) → CH3NH42+(aq)

C.

NO3−(aq) + H+(aq) → HNO3(aq)

D.

OH−(aq) + H+(aq) → H2O(l)

💡 Solution & Explanation

STEPS:

1. Identify the components of the buffer system: The buffer solution is prepared by mixing the weak base methylamine (CH3NH2\text{CH}_3\text{NH}_2) and its conjugate acid, the methylammonium ion (CH3NH3+\text{CH}_3\text{NH}_3^+), which is provided by the soluble salt methylammonium chloride (CH3NH3Cl\text{CH}_3\text{NH}_3\text{Cl}).
2. Analyze the species introduced by the added strong acid: Nitric acid (HNO3\text{HNO}_3) is a strong acid that dissociates completely in aqueous solutions to release hydrogen ions (H+\text{H}^+) into the system.
3. Determine the buffering reaction: When a strong acid is added to a buffer, the weak base component of the buffer system reacts to consume the added H+\text{H}^+ ions.
4. Formulate the reaction equation: The weak base methylamine (CH3NH2\text{CH}_3\text{NH}_2) acts as a proton acceptor, neutralizing the added H+\text{H}^+ and converting it to the weak conjugate acid methylammonium (CH3NH3+\text{CH}_3\text{NH}_3^+):
CH3NH2(aq)+H+(aq)CH3NH3+(aq)\text{CH}_3\text{NH}_2(aq) + \text{H}^+(aq) \rightarrow \text{CH}_3\text{NH}_3^+(aq)
5. Relate the reaction to the pH stability: Because the added strong H+\text{H}^+ ions are successfully converted into a weak conjugate acid, the concentration of free H+\text{H}^+ in the solution increases only slightly, which keeps the pH from changing significantly (only dropping from 10.64 to 10.62). This reaction perfectly matches Option A.

*

WHY_OTHERS_WRONG:

  • Option B is incorrect: The methylammonium ion (CH3NH3+\text{CH}_3\text{NH}_3^+) is already the conjugate acid of the system. Due to positive-charge repulsion, it will not accept another proton under these conditions to form a highly unstable divalent ion (CH3NH42+\text{CH}_3\text{NH}_4^{2+}).
  • Option C is incorrect: Because nitric acid (HNO3\text{HNO}_3) is a strong acid, its conjugate base (NO3\text{NO}_3^-) is extremely weak and has negligible basicity. Nitrate will not react with H+\text{H}^+ to reform molecular HNO3\text{HNO}_3 in an aqueous solution.
  • Option D is incorrect: While H+\text{H}^+ can react with free hydroxide ions (OH\text{OH}^-) to form water, the concentration of free hydroxide ions in this buffer is very low. The principal component responsible for the buffering capacity against added acid is the weak base CH3NH2\text{CH}_3\text{NH}_2 itself, which is present in a much higher concentration.
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