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Acids and BasesMCQ

Questions 26-28 refer to the following information. The structure of haloacetic acids, XCH2COOH (wheAcids and Bases Chemistry Question

Question

Questions 26-28 refer to the following information.

The structure of haloacetic acids, XCH2COOH (where X is either F, Cl, Br, or I ), is shown below.

[VISUAL]

A student titrates 10.0 mL samples of 1.0 M solutions of each of the haloacetic acids with a standard solution of NaOH. Which of the following statements correctly predicts the volume of NaOH(aq) needed to reach the equivalence point?

A.

Fluoroacetic acid will need the smallest volume of NaOH(aq) to reach the equivalence point.

B.

Iodoacetic acid will need the smallest volume of NaOH(aq) to reach the equivalence point.

C.

All of the acids will need the same volume of NaOH(aq) to reach the equivalence point.

✓ Correct
D.

All of the haloacetic acids are weak; therefore none will reach an equivalence point.

💡 Solution & Explanation

STEPS:

1. Identify the chemical equation and stoichiometry of the reaction:
All four haloacetic acids—fluoroacetic, chloroacetic, bromoacetic, and iodoacetic acid—are monoprotic weak acids. When titrated with sodium hydroxide, they react according to a 1:11:1 stoichiometric ratio where one mole of hydroxide ions reacts with one mole of the monoprotic acid to form water and the conjugate base:
HA(aq)+OH(aq)A(aq)+H2O(l)\text{HA}(aq) + \text{OH}^-(aq) \rightarrow \text{A}^-(aq) + \text{H}_2\text{O}(l)

2. Define the equivalence point of a titration:
The equivalence point in an acid-base titration is the point at which the number of moles of added titrant (NaOH\text{NaOH}) is stoichiometrically equal to the number of moles of acid analyte originally present in the sample. For a monoprotic acid titrated with a monoprotic strong base, this occurs when the moles of OH\text{OH}^- added equals the moles of HA\text{HA} originally present in the flask.

3. Calculate the moles of analyte present in each titration flask:
The problem specifies that the student titrates 10.0 mL10.0\text{ mL} samples of 1.0 M1.0\text{ M} solutions of each of the haloacetic acids. Because the initial concentrations and volumes are identical across all trials, each sample contains the exact same number of moles of acid analyte:
Moles of Acid=Molarity×Volume=1.0 mol/L×0.0100 L=0.010 mol of Acid\text{Moles of Acid} = \text{Molarity} \times \text{Volume} = 1.0\text{ mol/L} \times 0.0100\text{ L} = \mathbf{0.010\text{ mol of Acid}}
Thus, equimolar amounts of each acid are being analyzed.

4. Determine the required volume of titrant:
Because every sample contains exactly 0.010 mol0.010\text{ mol} of a monoprotic acid, each titration requires exactly 0.010 mol0.010\text{ mol} of NaOH\text{NaOH} to reach the equivalence point. Since the exact same standard NaOH\text{NaOH} solution is used as the titrant for all runs, the volume of NaOH\text{NaOH} solution needed to supply this amount of base is identical for all four acids, identifying Option C as the correct choice.

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WHY_OTHERS_WRONG:

  • Options A and B are incorrect: These options suggest that fluoroacetic acid or iodoacetic acid would require a smaller volume of base to reach the equivalence point. Students often make this mistake by confusing acid strength (indicated by KaK_a or percent ionization) with the total amount of neutralizing base needed. While fluoroacetic acid is the strongest of these weak acids (highest KaK_a) and iodoacetic acid is the weakest (lowest KaK_a), titration equivalence points depend entirely on the total moles of acidic protons present, not on the degree to which those acids dissociate in water before titration.
  • Option D is incorrect: This option claims that because the haloacetic acids are weak, they will not reach an equivalence point. This is a fundamental misconception; weak acids absolutely reach a stoichiometric equivalence point when titrated with a strong base because the strong base drives the neutralization reaction to completion.

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🌡️ Question 29 is the next in this exam sequence and asks about the autoionization of water at an elevated temperature of 40°C. Would you like to walk through how to calculate the pH of pure water under these conditions?

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