The following information applies to parts A and B. 5. The Lewis diagram of CBrClF2 is shown. — Bond Polarity, VSEPR Theory, Intermolecular Forces Chemistry Question

Which of the bonds in CBrClF₂ (C^-Br, C^-Cl, or C^-F) is the most polar? Justify your answer.

In a molecule of CBrClF₂, the F^-C^-F bond angle is 106.8° and the Br^-C^-Cl bond angle is 112.3°. Explain the difference in bond angles using principles of atomic structure and VSEPR theory.

Lewis diagrams and boiling points for CBr₄ and CBrClF₂ are given in the following table.

i. Clearly identify all the intermolecular forces in pure CBr₄(l) and in pure CBrClF₂(l).
CBr₄(l):
CBrClF₂(l):

ii. In terms of the relative strengths of all the intermolecular forces, explain why pure CBr₄(l) has a higher boiling point than pure CBrClF₂(l) does.