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Acetic acid: pKa = 4.76 Sulfuric acid: pKa2 = 1.99 Citric acid: pKa1 = 3.10, pKa2 = 4.35, pKa3 = 6.3Analytical Chemistry Chemistry Question

Analytical Concentrations and pH Calculations

Acetic acid: pKa = 4.76
Sulfuric acid: pKa2 = 1.99
Citric acid: pKa1 = 3.10, pKa2 = 4.35, pKa3 = 6.39

7.1.

Calculate the analytical concentration for each of the following solutions:
7.1 HCl solution, pH = 4.00 (solution A),

Model Answer

7.1 [H3O+] = 1×10^−4
c(HCl)total = 1×10^−4 mol dm^–3

7.2.

Calculate the analytical concentration for each of the following solutions:
7.2 acetic acid solution, pH = 4.00 (solution B),

Model Answer

7.2 [H3O+] = 1×10^−4
Mass balance: [HAc]total = [Ac−] + [HAc]
Charge balance: [H3O+] = [Ac−]
[H3O+][Ac−] / [HAc] = [H3O+]^2 / ([HAc]total - [H3O+]) = Ka
[HAc]total = 6.75×10^−4

7.3.

Calculate the analytical concentration for each of the following solutions:
7.3 sulfuric acid solution, pH = 4.00 (solution C),

Model Answer

7.3 [H3O+] = 1×10^−4
Mass balance: [H2SO4]total = [HSO4−] + [SO42−]
Charge balance: [H3O+] = [HSO4−] + 2[SO42−]
[H3O+][SO42−] / [HSO4−] = Ka2
The solution of the equations gives:
[H2SO4]total = 5.024×10^−5

7.4.

Calculate the analytical concentration for each of the following solutions:
7.4 citric acid solution, pH = 4.00 (solution D).

Model Answer

7.4 [H3O+] = 1×10^−4
Mass balance: [H3A]total = [H3A] + [H2A−] + [HA2−] + [A3−]
Charge balance: [H3O+] = [H2A−] + 2 [HA2−] + 3 [A3−]
[H3O+][H2A−] / [H3A] = Ka1
[H3O+][HA2−] / [H2A−] = Ka2
[H3O+][A3−] / [HA2−] = Ka3
[H3A]total = 8.29×10^−5

7.5.

Calculate the pH for each of the following mixtures:
7.5 equal volumes of solution A and NaOH solution (pOH = 4),

Model Answer

7.5 In the mixture of equal volumes of HCl and NaOH solutions [HCl]total = 5.00×10^−5 and [NaOH]total = 5.00×10^−5) the resulting solution is neutral and pH = 7.00.

7.6.

Calculate the pH for each of the following mixtures:
7.6 equal volumes of solution B and NaOH solution (pOH = 4),

Model Answer

7.6 In the mixture [HAc]total = 3.375×10^−4 and [NaOH]total = 5.00×10^−5
Material balance: [HAc]total = [Ac−] + [HAc]
Charge balance: [H3O+] + [Na+] = [Ac−]
[H3O+][Ac−] / [HAc] = Ka
[H3O+] = 4.46×10^−5 and [NaOH]total = [Na+]
pH = 4.35

7.7.

Calculate the pH for each of the following mixtures:
7.7 equal volumes of solution C and NaOH solution (pOH = 4),

Model Answer

7.7 In the mixture [H2SO4]total = 2.512×10^−5 and [NaOH]total = 5.00×10^−5, and thus, this solution is nearly neutral.
Material balance: [H2SO4]total = [HSO4−] + [SO42−], and [NaOH]total = [Na+]
Charge balance: [H3O+] + [Na+] = [HSO4−] + 2[SO42−] + [OH−]
Kw = [H3O+]·[OH−] = 1.00×10^−14
[H3O+][SO42−] / [HSO4−] = Ka2
[H3O+] = 2.76×10^−7
pH = 6.56

7.8.

Calculate the pH for each of the following mixtures:
7.8 equal volumes of solution D and NaOH solution (pOH = 4).

Model Answer

7.8 In the mixture [H3A]total = 4.145×10^−5 and [NaOH]total = 5.00×10^−5, the resulting solution contains: [NaH2A]total = 3.29×10^−5 and [Na2HA]total = 8.55×10^−6
[H3O+] = 2.00×10^−5
pH = 4.70

7.9.

Calculate the pH for each of the following mixtures:
7.9 equal volumes of solution A and B,

Model Answer

7.9 In the mixture [HAc]total = 3.375×10^−4 and [HCl]total = 5.00×10^−5,
Material balance: [HAc]total = [Ac−] + [HAc] and [HCl]total = [Cl−]
Charge balance: [H3O+] = [Ac−] + [Cl−]
[H3O+][Ac−] / [HAc] = Ka
[H3O+] = 9.99×10^−5 pH = 4.00

7.10.

Calculate the pH for each of the following mixtures:
7.10 equal volumes of solution A and C.

Model Answer

7.10 In mixture [H2SO4]total = 2.512×10^−5 and [HCl]total = 5.00×10^−5
Material balance: [H2SO4]total = [HSO4−] + [SO42−] and [HCl]total = [Cl−]
Charge balance: [H3O+] = [HSO4−] + 2[SO42−] + [Cl−]
[H3O+][SO42−] / [HSO4−] = Ka2
[H3O+] = 1.00×10^−4 pH = 4.00

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