What is the correct equilibrium expression for the given reaction? Cu(OH)2(s) + 4 NH3(aq) ⇌ Cu(NH3)4 — Equilibrium Chemistry Question
Question
What is the correct equilibrium expression for the given reaction?
Cu(OH)2(s) + 4 NH3(aq) ⇌ Cu(NH3)42+(aq) + 2 OH–(aq)
A.
Keq = [Cu(NH3)42+][OH–] / [NH3]
B.
Keq = [Cu(NH3)42+][2 OH–] / [4 NH3]
C.✓ Correct
Keq = [Cu(NH3)42+][OH–]2 / [NH3]4
D.
Keq = [Cu(NH3)42+][2 OH–]2 / [4 NH3]4
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