0.100 mol of HF (Ka = 6.6 × 10-4) is added to water to make 1.00 L of solution. Which statement is correct at equilibrium? | Acids and Bases

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Question

0.100 mol of HF (Ka = 6.6 × 10-4) is added to water to make 1.00 L of solution. Which statement is correct at equilibrium?

[H₃O⁺] = [HF]

[H₃O⁺] = 0.100 M

[HF] > [F–]

✓ Correct

[H₃O⁺] > [HF]

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