Sodium bicarbonate decomposes at high temperatures according to the following equation: 2 NaHCO3(s) — Equilibrium Chemistry Question
Question
Sodium bicarbonate decomposes at high temperatures according to the following equation:
2 NaHCO3(s) ⇌ Na2CO3(s) + CO2(g) + H2O(g)
At a certain temperature, 50.0 g of NaHCO3 is allowed to react in a 3.0 L evacuated vessel. At equilibrium, the total pressure is 6.25 atm, with some of both solids still present. If 100.0 g of NaHCO3 is allowed to react in the same vessel at the same temperature, what will the pressure be at equilibrium?
A.✓ Correct
6.25 atm
B.
8.84 atm
C.
12.5 atm
D.
25.0 atm
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