Ammonia is produced in accordance with this equation.
N₂(g) + 3H₂(g) → 2NH₃(g)
In a particular experiment, 0.25 mol of NH₃ is formed when 0.5 mol of N₂ is reacted with 0.5 mol of H₂. What is the percent yield?

Question

Ammonia is produced in accordance with this  equation.
N2(g) + 3H2(g) → 2NH3(g)
In a particular experiment, 0.25 mol  of NH3 is formed when 0.5 mol of N2 is reacted with 0.5 mol of H2. What is the  percent yield?

Accepted Answer

Correct answer: A.

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