A student isolates 22.0 g of ethyl bromide, C2H5Br (M = 108.96), from the reaction of 34.0 g of ethy — Stoichiometry Chemistry Question
Question
A student isolates 22.0 g of ethyl bromide, C2H5Br (M = 108.96), from the reaction of 34.0 g of ethyl alcohol (M = 46.07) with 59.0 g of phosphorus tribromide (M = 270.67) according to the balanced reaction below. What is the percent yield of the reaction?
3 C2H5OH(l) + PBr3(l) → 3 C2H5Br(l) + H3PO3(s)
A.
27.4%
B.✓ Correct
30.9%
C.
64.7%
D.
92.6%
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