Consider this equation and the associated value for ∆Ho. 2H2(g) + 2Cl2(g) → 4HCl(g) ∆Ho = –92.3 kJ W — Thermodynamics Chemistry Question
Question
Consider this equation and the associated value for ∆Ho.
2H2(g) + 2Cl2(g) → 4HCl(g) ∆Ho = –92.3 kJ
Which statement about this information is incorrect?
A.
If the equation is reversed, the ∆Ho value equals +92.3 kJ.
B.
The four HCl bonds are stronger than the four bonds in H2 and Cl2.
C.✓ Correct
The ∆Ho value will be –92.3 kJ if the HCl is produced as a liquid.
D.
23.1 kJ of heat will be evolved when 1 mol of HCl(g) is produced.
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