Fe2O3(s) + 3/2C(s) → 3/2CO2(g) + 2Fe(s) ∆H° = +234.1 kJ C(s) + O2(g) → CO2(g) ∆H° = –393.5 kJ Use th — Thermodynamics Chemistry Question
Question
Fe2O3(s) + 3/2C(s) → 3/2CO2(g) + 2Fe(s) ∆H° = +234.1 kJ
C(s) + O2(g) → CO2(g) ∆H° = –393.5 kJ
Use these equations and ∆H° values to calculate ∆H° for this reaction.
4Fe(s) + 3O2(g) → 2Fe2O3(s)
A.✓ Correct
–1648.7 kJ
B.
–1255.3 kJ
C.
–1021.2 kJ
D.
–129.4 kJ
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