4KO2(s) + 2CO2(g) → 2K2CO3(s) + 3O2(g) What is the maximum volume of oxygen that can be produced whe — Stoichiometry Chemistry Question
Question
4KO2(s) + 2CO2(g) → 2K2CO3(s) + 3O2(g)
What is the maximum volume of oxygen that can be produced when 150. mL of CO2 is passed over 0.500 g of KO2? Assume all gases are measured at 0 °C and 1 atm.
A.✓ Correct
118 mL
B.
157 mL
C.
225 mL
D.
475 mL
💬
Still have doubts about this question?
Practice more questions like this, completely free.