For the reaction; PbI2(s) ⇌ Pb2+(aq) + 2I–(aq) Ksp = 8.4×10-9 What is the concentration of Pb2+ in m — Equilibrium Chemistry Question
Question
For the reaction;
PbI2(s) ⇌ Pb2+(aq) + 2I–(aq) Ksp = 8.4×10-9
What is the concentration of Pb2+ in mol/L in a saturated solution of PbI2 in which [I–] = 0.01 M?
A.
8.4×10-7
B.✓ Correct
8.4×10-5
C.
1.3×10-3
D.
2.0×10-3
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