Calculate ∆E when one mole of liquid is vaporized at its boiling point (80 ˚C) and 1 atm pressure. [∆Hvap = 30.7 kJ/mol] | Thermodynamics

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ThermodynamicsMCQ

Question

Calculate ∆E when one mole of liquid is vaporized at its boiling point (80 ˚C) and 1 atm pressure.
[∆Hvap = 30.7 kJ/mol]

33.6 kJ

31.4 kJ

30.0 kJ

27.8 kJ

✓ Correct

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