Given the standard reduction potentials:
O₂ + ⁴H⁺ + 4e– → 2H₂O E˚ = 1.23 V
Br₂ + 2e– → ²Br – E˚ = 1.08 V
²H⁺ + 2e– → H₂ E˚ = 0.00 V
Na⁺ + e– → Na E˚ = –2.71 V
What products are formed in the electrolysis of 1 M NaBr in a solution with [H₃O⁺] = 1 M?

Question

Given the standard reduction potentials:
O2 + 4H+ +  4e– → 2H2O E˚ = 1.23 V
Br2 + 2e– → 2Br – E˚  = 1.08 V
2H+ + 2e– → H2 E˚ = 0.00 V
Na+ + e– → Na  E˚ = –2.71 V
What products are formed in the electrolysis of 1 M NaBr in a solution with [H3O+] = 1 M?

Accepted Answer

Correct answer: C.

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