Ag+(aq) + e– → Ag(s) E° = 0.80 V Mg2+(aq) + 2e– → Mg(s) E° = –2.73 V Use the equations above to calc — Electrochemistry Chemistry Question
Question
Ag+(aq) + e– → Ag(s) E° = 0.80 V
Mg2+(aq) + 2e– → Mg(s) E° = –2.73 V
Use the equations above to calculate the value of ∆G° (in kJ/mol) for the reaction:
Mg(s) + 2Ag+(aq) → Mg2+(aq) + 2Ag(s)
A.
681
B.
341
C.
–341
D.✓ Correct
–681
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