Iodide ion is oxidized by acidified dichromate ions as shown in this equation. Cr2O7 2–(aq) + 9I–(aq — Kinetics Chemistry Question
Question
Iodide ion is oxidized by acidified dichromate ions as shown in this equation.
Cr2O7 2–(aq) + 9I–(aq) + 14H+(aq) → 2Cr3+(aq) + 3I3 –(aq) + 7H2O(l)
These data were obtained when the reaction was studied at a constant pH.
What is the order of the reaction with respect to Cr2O7 2–(aq) and I–(aq)?
A.
first order with respect to both Cr2O7 2– and I–
B.
second order with respect to both Cr2O7 2– and I–
C.
second order with respect to Cr2O7 2– and first order with respect to I–
D.✓ Correct
first order with respect to Cr2O7 2– and second order with respect to I–
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