For the reaction: (CH3)3CBr(aq) + OH–(aq) → (CH3)3COH(aq) + Br–(aq) it is found that halving the con — Kinetics Chemistry Question
Question
For the reaction: (CH3)3CBr(aq) + OH–(aq) → (CH3)3COH(aq) + Br–(aq)
it is found that halving the concentration of (CH3)3CBr causes the reaction rate to be halved but halving the concentration of OH– has no effect on the rate. What is the rate law?
A.
Rate = k[(CH3)3CBr]1/2[OH–]
B.
Rate = k[(CH3)3CBr]2[OH–]
C.
Rate = k[(CH3)3CBr]1/2
D.✓ Correct
Rate = k[(CH3)3CBr]
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