Consider this reaction. 4PH3(g) + 8O2(g) → P4O10(s) + 6H2O(g) ∆Ho = –4500 kJ Calculate ∆Hfo of P4O10(s) in kJ·mol–1. | Thermodynamics

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ThermodynamicsMCQ

Question

Consider this reaction.
4PH₃(g) + 8O₂(g) → P₄O₁₀(s) + 6H₂O(g) ∆Ho = –4500 kJ
Calculate ∆Hfo of P₄O₁₀(s) in kJ·mol–1.

–5914 kJ

–4751 kJ

–4249 kJ

–3012 kJ

✓ Correct

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