CO(g) + 2 H2(g) ⇄ CH3OH(g) DH < 0 The synthesis of CH3OH(g) from CO(g) and H2(g) is represented by the equation above. The value of Kc for the reaction at 483 K | Equilibrium

Question

CO(g) + 2 H₂(g) ⇄ CH₃OH(g) DH < 0

The synthesis of CH₃OH(g) from CO(g) and H₂(g) is represented by the equation above. The value of Kc for the reaction at 483 K is 14.5.

Which of the following explains the effect on the equilibrium constant, Kc , when the temperature of the reaction system is increased to 650 K?

Kc will increase because the activation energy of the forward reaction increases more than that of the reverse reaction.

Kc will increase because there are more reactant molecules than product molecules.

Kc will decrease because the reaction is exothermic.

✓ Correct

Kc is constant and will not change.

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