Li3N(s) + 2 H2(g) <-> LiNH2(s) + 2 LiH(s) dH° = -192 kJ/mol_rxn Because pure H2 is a hazardous subst — Equilibrium Chemistry Question
Question
Li3N(s) + 2 H2(g) <-> LiNH2(s) + 2 LiH(s) dH° = -192 kJ/mol_rxn
Because pure H2 is a hazardous substance, safer and more cost effective techniques to store it as a solid for shipping purposes have been developed. One such method is the reaction represented above, which occurs at 200°C.
The amount of H2(g) present in a reaction mixture at equilibrium can be maximized by
A.
increasing the temperature and increasing the pressure by decreasing the volume
B.✓ Correct
increasing the temperature and decreasing the pressure by increasing the volume
C.
decreasing the temperature and increasing the pressure by decreasing the volume
D.
decreasing the temperature and decreasing the pressure by increasing the volume
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