What will be the result when 15.0 mL of 0.040 M lead(II) nitrate is mixed with 15.0 mL of 0.040 M so — Aqueous Chemistry Chemistry Question
Question
What will be the result when 15.0 mL of 0.040 M lead(II) nitrate is mixed with 15.0 mL of 0.040 M sodium chloride?
PbCl2(s) ⇌ Pb2+(aq) + 2 Cl–(aq) [Ksp = 1.7 × 10–5]
A.✓ Correct
A clear solution with no precipitate will result.
B.
Solid PbCl2 will precipitate and excess Pb2+ ions will remain in solution.
C.
Solid PbCl2 will precipitate and excess Cl– ions will remain in solution.
D.
Solid PbCl2 will precipitate and no excess ions will remain in solution.
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