Given the enthalpy changes: A + B → C ∆H = –35 kJ•mol–1 A + D → E + F ∆H = +20 kJ•mol–1 F → C + E ∆H — Thermodynamics Chemistry Question
Question
Given the enthalpy changes:
A + B → C ∆H = –35 kJ•mol–1
A + D → E + F ∆H = +20 kJ•mol–1
F → C + E ∆H = +15 kJ•mol–1
What is ∆H for the reaction 2A + B + D → 2 F?
A.
0 kJ•mol–1
B.✓ Correct
–30 kJ•mol–1
C.
–40 kJ•mol–1
D.
–70 kJ•mol–1
💬
Still have doubts about this question?
Practice more questions like this, completely free.